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edu/pluginfile.php/2 161240 mod resource content/0/08%20Synthesis%20of%20Aspinn.pdf Experiment 8 Synthesis of Aspirin Report Due: Week of April 23 Pre-Lab Questions: Complete the Following Table MW Equiv mL 5.0 mmol Acetic Anhydride Salicylic acid Sulfuric 15 XxX 0.05 acid, cone. Safety Precautions: Acetic anhydride is irritating to the nose and sinuses. Keep this compound under the hood at all times, and avoid breathing the vapors. The aspirin that you make in this lab is NOT pure enough to be taken internally! Do not ingest the aspirin! Aspirin: Aspirin is an effective analgesic (pain reliever), antipyretic (fever reducer) and anti-inflammatory agent and is one of the most widely used non-prescription drugs. The use of aspirin had its origin in the 18h century, when it was found that an extract from the bark of willow trees was useful inExplanation / Answer
Experiment 8-
Acetic anhydride
Molecular weight= 102.09 g/mol
Equivalent weight= 102.09/6=17.02 ( 6 valence of acetic anhydride)
mmol:
Mol=mass(g)/molecular wt.=5.15 /102.09=0.0504mol
mmol=mol*1000= 0.0504*1000=50.4 mmol
g = volume*density= 5ml(given)*1.08=5.4
d = density= 1.09 g/ml
Volume= 5 ml (given)
Salicylic acid
Molecular weight=138.12 g/mol
Equivalent wt= 138.12/6= 23.02
mmol= 15 (given)
Mol=0.015 mol
g m= 2.88 ( using formula g= v*d, d and v is given)
d= 1.44 g/ml
Volume = 2ml
Sulfuric acid
Molecular weight= 98.09 g/mol
Equivalent wt= 49.04
Mmol
Mol = 1.85 g/ml*0.05 ml=0.0925mol
0.0925*1000=92.5 mmol
g= 0.092
d=1.84 g/ml
Volume=0.05 ml
Experiment 9-
Sebacoyl chloride
Molecular weight= 239.14 g/mol
Equivalent wt.= 239.14/16=14.95 (16 is Valence i.e no.of H atoms)
mmol=
Mol= mass/molecular weight=0.412/239.14=0.0017mol
Mmol=0.0017*1000=1.7mmol
g= v*d=0.4ml*1.12=0.448
d= 1.12 g/cc
Volume= 0.4 ml
1,6hexane diamine
Molecular weight= C6H16N2=(6*12.01)+(16*1.008)*(2*14.01)=116.21g/mol
Equivalent wt=116.21/16=7.26
mmol=0.05mol(given)*1000=50 mmol
g=0.22 (given)
d=0.5 molar solutions
Volume= g/density=0.22/0.84=0.262g/cc
NaOH
Molecular weight= 39.997 g/mol
Equivalent wt.=39.997/1=39.997
Mmol= 0.1mol*1000=100mmol
g=v*d=4ml*2.13=8.52
d=1.0molar solution
Volume=4ml(given)
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