a) When 25.0 mL of a 1.49×10 -4 M potassium hydroxide solution is combined with

Question

a) When 25.0 mL of a 1.49×10-4M potassium hydroxide solution is combined with 25.0 mL of a 4.16×10-4M manganese(II) iodide solution does a precipitate form?  (yes or no)

For these conditions the Reaction Quotient, Q, is equal to .

b) When 15.0 mL of a 5.58×10-4 M aluminum bromide solution is combined with 12.0 mL of a 4.14×10-4 M potassium phosphate solution does a precipitate form?   (yes or no)

For these conditions the Reaction Quotient, Q, is equal to. .

c) When 15.0 mL of a 5.22×10-4 M silver nitrate solution is combined with 25.0 mL of a 6.19×10-4 M ammonium iodidesolution does a precipitate form?   (yes or no)

For these conditions the Reaction Quotient, Q, is equal to .

Explanation / Answer

a) yes , Mg(OH)2(s)

Reaction Quotient Q = [Mg2+][OH-]^2

             [Mg2+] = (4.16*10^-4*25/50) = 2.08*10^-4 M

              [OH-] = (1.49*10^-4*25/50) = 7.45*10^-5 M

   Q = (2.08*10^-4)*(7.45*10^-5)^2

     = 1.15*10^-12

b) yes , AlPO4

Reaction Quotient Q =[Al3+][PO43-]

[Al3+] = ( 5.58*10^-4*15/27) = 3.1*10^-4 M

[PO4^3-] = (4.14*10^-4*12/27) = 1.84*10^-4 M

Q = (3.1*10^-4)*(1.84*10^-4)

= 5.704*10^-8

c) yes, AgI

Reaction Quotient Q =[Ag+][I-]

[Ag+] = (5.22*10^-4*15/40) = 1.96*10^-4 M

[I-] = (6.19*10^-4)*25/40 = 3.87*10^-4 M

Q = (1.96*10^-4)*(3.87*10^-4)

   = 7.58*10^-8

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