1. The apparatus shown below consists of three 1.00L bulbs connected by stopcock
ID: 104654 • Letter: 1
Question
1. The apparatus shown below consists of three 1.00L bulbs connected by stopcocks and held at the temperatures shown. Bulb A contains a mixture of H2O, CO2, and N2 at 25°C and a total pressure of 564 mmHg. Bulbs B and C are empty. CO2 sublimes at -78°C and N2 boils at -196°C 25 °C -70 -190 °C a. The stopcock between A and B is opened. The pressure in A and B is now 219 mmlHg. What do bulbs A and B contain? (5 points) b. How many moles of H20 are in the system(5 points) c. Both stopcocks are opened. The pressure throughout the system is 33.5mmHg. What do bulbs A, B and C contain? (10 points) d. How many moles of N2 are in the system? (10 points) c. How many moles of CO2 are in the system? (10 points)Explanation / Answer
a. at - 70 c , H2o(g) converts into ice = H2o(s), other two are gases only.
no of mol of gas in A before openining stopcock
= PV/RT
= ((564/760)*1)/(0.0821*298)
= 0.0303 mol
after openining stopcock
no of mol of gas mixture = PV/RT
= ((219/760)*1)/(0.0821*298)
= 0.012 mol
b) no of mol of water = 0.0303 - 0.012 = 0.0183 mol
c) after openining both stopcocks,
bulb A contains = water,N2
bulb B contains = water, N2
bulb C, contains = CO2, N2
D) No of mol of N2 = PV/RT
= ((33.5/760)*1)/(0.0821*298)
= 0.0018 mol
c) No of mol of CO2 in the system = 0.0303- (0.012+0.0018) = 0.0165 mol
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