Part A ? H ?rxn=+ 127 kJ ; ? S ?rxn=? 263 J/K ; T = 293 K Submit Request Answer

Question

Part A

?H?rxn=+ 127 kJ ; ?S?rxn=? 263 J/K ; T= 293 K

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Part B

?H?rxn=? 127 kJ ; ?S?rxn=+ 263 J/K ; T= 293 K

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Part C

?H?rxn=? 127 kJ ; ?S?rxn=? 263 J/K ; T= 293 K

Express your answer using two significant figures.

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Part D

?H?rxn=? 127 kJ ; ?S?rxn=? 263 J/K ; T= 553 K

Express your answer using two significant figures.

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Part E

Predict whether or not the reaction in part A will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part A will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

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Part F

Predict whether or not the reaction in part B will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part B will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

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Part G

Predict whether or not the reaction in part C will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part C will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

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Part H

Predict whether or not the reaction in part D will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part D will be spontaneous at the temperature indicated. (Assume that all reactants and products are in their standard states.)

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?G?rxn =   kJ  

Explanation / Answer

A)

deltaHo = 127.0 KJ

deltaSo = -263 J/K

= -0.263 KJ/K

T = 293 K

we have below equation to be used:

deltaGo = deltaHo - T*deltaSo

deltaGo = 127.0 - 293.0 * -0.263

deltaGo = 204 KJ

Answer: 2.0*10^2 KJ

B)

deltaHo = -127.0 KJ

deltaSo = 263 J/K

= -0.263 KJ/K

T = 293 K

we have below equation to be used:

deltaGo = deltaHo - T*deltaSo

deltaGo = -127.0 - 293.0 * 0.263

deltaGo = -204 KJ

Answer: -2.0*10^2 KJ

C)

deltaHo = -127.0 KJ

deltaSo = -263 J/K

= -0.263 KJ/K

T = 293 K

we have below equation to be used:

deltaGo = deltaHo - T*deltaSo

deltaGo = -127.0 - 293.0 * -0.263

deltaGo = -49.9 KJ

Answer: -50. KJ

D)

deltaHo = -127.0 KJ

deltaSo = -263 J/K

= -0.263 KJ/K

T = 553 K

we have below equation to be used:

deltaGo = deltaHo - T*deltaSo

deltaGo = -127.0 - 553.0 * -0.263

deltaGo = 18 KJ

Answer: 18 KJ

E)

Since deltaGo is positive,

it is non spontaneous

Answer: No

F)

Since deltaGo is negative,

it is spontaneous

Answer: Yes

G)

Since deltaGo is negative,

it is spontaneous

Answer: Yes

H)

Since deltaGo is positive,

it is non spontaneous

Answer: No

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