A) 0.987 atmU B) 1.35 atm C) 1.84 atm D) 0.255 atm n212 the parti 3) A mixture o

Question

A) 0.987 atmU B) 1.35 atm C) 1.84 atm D) 0.255 atm n212 the parti 3) A mixture of 100 g of Ne and 100 g Af have a total presksure of 1.,6 atm. What is t pressure of Ne? A) 0.80 atm B) 0.54 atm C) 0.40 atm D) 1.3 atm E) 1.1 atm 4) A basketball is inflated to a pressure of 1.80 atm in a 23.0°C garage. What is the press basketball outside where the temperature is -2.00°C? B) 1.70 atm C) 1.90 atm D) 1.97 atm A) 1.65 atm 5) Which of the following solutions will have the highest electrical conductivity? A) 0.15 M LiF B) 0.10 M LiBr C) 0.040 M (NH4)2CO3 D) 0.045 M Al2(S04):3 E) 0.15 M Nal

Explanation / Answer

Answer:

Molar mass of Ne = 20.2 g/mol, Molar mass of Ar = 40.0 g/mol

Mass of Ne taken = 10.0 g Mass of Ar = 10.0

# of moles of Ne = 10.0 / 20.0 = 0.50 moles

# of Moles of Ar = 10.0 / 40.0 = 0.25 moles

Total # of moles 0.50 + 0.25 = 0.75 moles.

Mole Fraction of Ne = Moles of Ne / Total # of moles = 0.50 / 0.75 = 2/3.

Total pressure = 1.6 atm

Partial pressure of Ne = Mole fraction of Ne * Total pressure = (2/3) * 1.6 = 1.066 atm = 1.1 atm (rounded)

Answer option : E) 1.1 atm

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