QUESTION A S00 mL smple or 0436 M NH?NO, is diluted with water to toal volume of

Question

QUESTION A S00 mL smple or 0436 M NH?NO, is diluted with water to toal volume of 250.0 mL. What is the ammonium nitrate concentratio in the resulting solution? 0.100M 0.028M 0.0872M ? 0.0752M QUESTION 2 During a titration the following data were collected. A 10. mL portion of an unknown monoprotic acid solution was titrated with 1.O M NaoH; 40. mL of the base were required to neutralize the sample. What is the molarity of the acid solution? 2.0 M 1.0 M O 4.0 M 0.5 M QUESTION 3 0.500 M NaOH, 200. ml of the During a titration the following data were collected. A 50.0 mL. portion of an HCI solution was titrated with base was required to neutralize the sample. How many grams of HCI are present in 500.ml of this acid solution? 5.85g 7.30g 3.659 1.82g QUESTION 4 A 0.00100 mol sample of Ca(OH concentration of the HC1? 102 requires 25.00 mL of aqueous HCI for neutralization according to the reaction below. What is the 2HC?(aq) ? CaCl2(aq) H2O(1) + + Ca(OH)2(s) 0.0200 M 0.0400 M 0.0800 M 4.00 x 10-5 AM

Explanation / Answer

1) molarity of initial solution, M1 = 0.436 M

Vol. Of initial solution, V1 = 50 ml

vol. Of final solution after dilution,V2 = 250 ml

Molarity of final solution,M2 = M

M1V1 = M2V2

0.436×50 = M x 250

M = 0.0872 = molarity of ammonium nitrate after dilution

2) molarity of base M1 = 1M

Vol of base V1 = 40 ml

Molarity of acid M2 = M

Vol of acid V2 = 10 ml

M1V1 = M2V2

1x40 = M x 10

M = 4 M = molarity of monoprotic acid

3) molarity of base M1 = 0.5 M

Vol of base, V1 = 200 ml

Molarity of acid M2 = M

Vol of acid V2 = 50 ml

M1V1 = M2V2

0.5x200 = M x 50

M = 2 Molarity of acid HCl

Molarity of HCl = (wt taken/molar mass)/vol in lts

2 = no. Of moles/0.05

No. Of moles = 0.1

No. Of HCl moles = wt taken/ 36.5 =0.1

So. Mass of HCl used is 3.65 gms

4) Ca(OH)2 + 2HCl. ----> CaCl2 + 2H2O

molar ratio of calcium hydroxide : HCl = 1:2

So 0.001 moles of Ca(OH)2 --- ? 0.001x2 = 0.00200 moles of HCl

Vol of HCl = 25 ml = 0.025 lts

Molarity of HCl = no. Of moles/vol in lts = 0.00200/0.025 =

0.0800 M

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