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What is the chemical basis of enzyme catalysis? What is the Michaelis-Menten equ

ID: 1047968 • Letter: W

Question

What is the chemical basis of enzyme catalysis? What is the Michaelis-Menten equation and its Lineweaver-Burk form? How does the Michaelis-Menten equation explain why the rate of an enzyme catalyzed reaction is proportional to the amount of enzyme? How does the Michaelis-Menten equation explain why the rate of an enzyme catalyzed reaction reaches a maximum value at high substrate? A reaction S P is catalyzed by two enzymes, A and B. The reaction coordinate diagrams for these enzymes are shown below. Which of the two enzymes binds tighter to the substrate? Explain your reasoning Which step in each reaction is the rate-limiting step? Explain Which of the two enzymes is a better catalyst? Explain your reasoning

Explanation / Answer

Enzmyes are also called as bio-catalysts, They are having active site where the substrate can bind. the substrate and active sire of the enzyme are complimentary chemically as well as from structure point of view. That is why Enzymes are very specific in nature due to their compatability with the substrates.

2. Michaelis menten kinetic is given by V= Vmax[S] / [KM+S]

Where V= rate of reaction, Vmax= Maximum rates, S is substrate concentration. KM is Michaelis menten constant

3. The above equaition can alos be written as 1/V= (KM/Vmax) 1/S + 1/Vmax

The above equation is known as Lineweaver- burk plot

4. V= Vmas [S] / [KM+S]

Vmax = KCat[ E] total, Etoal = Enzyme concentration

V= Kcat[ E] [S]/ [KM+S]

this suggests that the rate V to be proportional to Enzyme concentration

5. V= Vmax [S] / (KM+S]

at high substrate concentration KM+S is approximately equal to KM

hence V= Vmax [S]/[S] = Vmax

So at high substrate concentration , V= Vmax

6. In case of A gibbs free energy change is maximum, Hence Enzyme binds tigher to the enzyme.

7. the rate limiting step is ES to EP in both the enzmyes since gibbs free energy change is maximum in both the transition from ES to EP

8. since gibbs free energy change is less for B, B is better catalsy

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