Answer the following questions in your lab notebook: 1. Give the chemical formul
ID: 104814 • Letter: A
Question
Answer the following questions in your lab notebook: 1. Give the chemical formula for a single chemical reagent that would: (a) separate Ag from Cu (b) separate AgCl from PbClz (c) separate Cu from Mn2 (d) separate Fe from Zn (e) Dissolve Zn(OH)2 but not Fe(OH (1) separate Ba from Mn2 and Zn 2. Write balanced ionic chemical equations for a· The dissolution of AgCl in excess ammonia b. The precipitation of Pb to PbCrOs(s) c. The hydrolysis of thioacetamide (CH:CSNH2) at high temperature to yield H2S gas. d. The precipitation of Cu by H2S in acidic medium. e· The complex formation of Cu2+ in ammonia solution. f. The complex formation of Fe in KSCN solution. g. The oxidation of Mn2 to MnO4 using NaBiO, solution in acidic medium. h. Write two ionic equations to illustrate the amphoteric nature of Zn(OH2. i. The confirmation test for NH4 j· The confirmation test for Ba2+ (not the flame test.) 3. Write the step-wise net ionic equations for all the cations that show amphoteric ion although it was not tested in the behavior in excess NaOH solution. (include Al lab.) Write the balanced net ionic equations for all the cations which exhibit complex formation with ammonia. (include Ni2 and Co although they were not tested in the lab.) 4.Explanation / Answer
a: Add dilute HCl to the solution containing Ag+ and Cu2+ , due to low solubility Ag+ will be precipiteted as AgCl. Hence the reagent is dilute HCl
b: When we add hot water, PbCl2 being more soluble is dissolved leaving the precipitation of AgCl. Hence the reagent is hot H2O
c: Add H2S under acidic cndition. Cu2+ is precipitated as CuS due to low solubility leaving Mn2+ unreacted. Hence the reagent is H2S under acidic condition.
d: Add NaOH to the solution. Fe3+ is precipitated as Fe(OH)3 due to low slubility. Hence the reagent is NaOH.
f: Add ammonium carbonate ion to the solution containing Ba2+, Mn2+ and Zn2+. Ba2+ is precipitated as BaCO3 leaving the remaining two ions in the solution. Hence the reagent is (NH4)2CO3
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