Which of the following responses correctly arranges the acids according to acid

Question

Which of the following responses correctly arranges the acids according to acid strength? HIO > NIO_2 > HIO_2 HBr > HF > HCl HFO_2 > HClO_2> HIO_2 > HIO > HIO_2 HF > NH_3 > H_2O A 5.00-1 flask initially contained 0.700 mol CO_2, 1.300 mol CO, and 0.400 mol O_2 at 2000 K. The equilibrium constant [K._e] for the following reaction is .778 at 2000 K. 2 CO_2 irreversible 2 CO + O_2 The value of Q is and the. 1.38, concentration of CO_2 will decrease as the system approaches equilibrium 1.38, concentration of CO_2 will decrease as the system approaches equilibrium 0.725, concentration of CO_2 will decrease as the system approaches equilibrium 0.725, concentration of CO_2 will increase as the system approaches equilibrium 0.276, concentration of CO_2 will decrease as the system approaches equilibrium 3.620, concentration of CO_2 will increase as the system approaches equilibrium If the pOH of a solution is 8.30, the [H^+] of that solution is M. 5.70 times 10^6 5.70 5.01 times 10^-9 1.75 times 10^-15 indicate some other answer The pH of a 0.00875 M Ra(OH)_2 solution is .2.06 12.2 1.76 11.9 indicate some other answer The pH of a 1 times 10^-11 M CSOH solution is: 3 11 -3 slightly >7 slightly

Explanation / Answer

Q8.

a) false, since more Oxygens make it more acidic

b)

Halse, sinc eHcl is strongest

c)

TRUE

HFO3 > HClO2 > HBrO is true

d)

false, since HIO <HIO2 due to number of oxgyens

e)

icorrect, we have acid > base > water, and a bas eis always more basic

9

V = 5 l

[CO2] = mol/V= 0.7/5 = 0.14 M

[CO] = 1.3/5 = 0.26M

[O2] = 0.4*5 = 0.08M

K = 0.778

then..

find Q

Q = [CO]^2[O2] / [CO2]

Q = 0.26^2 * 0.08 / (0.14^2) = 0.275918

choose D

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