Starting alcohol: n-butanol Acetic acid will be used You will start with 500 mg

Question

Starting alcohol: n-butanol Acetic acid will be used You will start with 500 mg of one of your starting alcohol (whichever one you will be using to generate your product). While the alcohols are liquids, we will measure them by mass directly on the balance, not by volume (i.e. the density of the alcohol will not be used: pretend the alcohol is a solid). Acetic acid (or propionic acid) will be measured by volume. Determine the volume of acetic acid (or propionic acid) to add that will correspond to 4.0 molar equivalents based on mmols of stalling alcohol.

Explanation / Answer

moles of alcohol = weight/molecular mass= .5/74.12 = .0067 moles (this is one equivalent)

4 equivalents of acetic acid= 4 * .0067 moles = .02698 moles

mass = .02698 * 60.05 = 1.62 g

volume = mass / density = 1.62 / 1.05 = 1.54 mL

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