PROBLEM 8-11 Calculate the mass of titanium metal required to absorb each kilogr

Question

PROBLEM 8-11 Calculate the mass of titanium metal required to absorb each kilogram of hydrogen and form TiH2 in a "tankful" of hydrogen. Repeat the calculation for magnesium if the hydride has the formula MgH2. Which metal is superior for storage of hydrogen from a weight standpoint? PROBLEM 8-12 Assuming that the energy released by combustion of H2 is proportional to the amount of oxygen it consumes, estimate the ratio of heat released by one mole of methane compared to one mole of hydrogen gas. PROBLEM 8-13 Using the thermochemical information in the H combustion equation, cal culate the enthalpy (heat) of combustion of hydrogen per gram, and by com- paring it to that of methane (see Problem 7-4), decide which fuel is superior on a weight basis. By comparing the actual energy released by combustion per mole of gas-and hence per molar volume-decide which fuel is superior on a volume basis

Explanation / Answer

Ans 8-11

Each mole of TiH2 has 2 moles of hydrogen atoms

So 47.867 g of Ti has 2.016 g of Hydrogen

So amount of Ti will to absorb 1 kg of hydrogen will be : ( 1000 x 47.867) / 2.016

= 23743.6 g of Titanium

Now 1 mole of MgH2 has 24.305 g of Mg and 2.016 g of H2

So 1 kg of hydrogen will be absorbed by ( 1000 x 24.305) / 2.016

= 12056 g of Magnesium

So we can see that magnesium is more superior for the storage of hydrogen from weight standpoint.

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