What is the formula weight of NaNO_3? Calculate the molarity of a solution produ

Question

What is the formula weight of NaNO_3? Calculate the molarity of a solution produced by dissolving 135.5 g of NaNO_3 in a 500 mL volumetric flask? You mix 6.0 mL if 0.50 M Na_2SO_4 with 8.0 mL of 0.50 M Pb(NO_3)_2, and collect and dry the PbSO_4 precipitate. Calculate the following: Moles of Na_2SO_4 used: Moles of Pb(NO_3)_2 used: Moles of PbSO_4 precipitate expected from Na_2SO_4; Moles of PbSO_4 precipitate expected from Pb(NO_3)_2: What mass of PbSO_4 do you expect to obtain from this reaction? If the actual mass of the precipitate you recover is 0.78 g, what is the percent recovery of the precipitate?

Explanation / Answer

7. Formula weight of a substance is equal to the sum of atomic masses of its constituent atoms.

We know atomic weight of Na:-23, N:-14, O:- 16

Formula weight of NaNO3 is:- 23+14+48:-85g

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