Gradeb 11/5/2016 11:55 PM S74Al100 11/4/2016 11:34 AM Print Periodic Table 15 of

Question

Gradeb 11/5/2016 11:55 PM S74Al100 11/4/2016 11:34 AM Print Periodic Table 15 of 15 Mapo Sapling Learning Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(Ivy axide: You add 41.3 g of Mnoz to a solution containing 41.5 g of HCI. (a) What is the limiting reactant? O Mno2 HCI (b) What is the theoretical yield of Cla? g Cl, (c) the yield of the reaction is 71.1%, what is the actual yield of chlorine? Previous Give up s view soution Check Answer ONeat HExe careers partners privacy policy l terms of use concact us help acBook Pro

Explanation / Answer

4HCl + MnO2 -------------> MnCl2 + 2H2O + Cl2

36.5g 86.94g 125.84g (Molar masses)

4 moles or HCl react with one mole of MnO2 to give one mole of MnCl2 and two moles of water and one mole of Cl2

HCl: 41.5 g = 41.5/35.5 gmol-1 = 1.136 mole

MnO2: 41.3/86.94 gmol-1 = 0.475 mole

1.136 mole of HCl require 0.284 moles of MnO2. So we have excess of MnO2.

So the limiting reagent is HCl.

b. Theoretical yield of Cl2

4 moles or HCl react with one mole of MnO2 to give one mole of MnCl2 and two moles of water and one mole of Cl2

1.136 mole of HCl require 0.284 moles of MnO2 to produce 0.284 moles of Cl2 or 71.0 g of Cl2.

b. 71.1% of Cl2 :

71.1/100 x 71 = 50.48g

50.48g of Cl2 is produced

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