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Need to find the amount of benzoin used in moles, the isolated yield in moles, t

ID: 1051205 • Letter: N

Question

Need to find the amount of benzoin used in moles, the isolated yield in moles, theoretical yield in grams and moles and percent yield please!

Procedure (Dilantin by multistep synthesis)

In a 25 mL round-bottomed flask place 350 mg of unrecrystallized benzoin, 1.0 mL of glacial acetic acid, 160 mg of pulverized ammonium nitrate, and 0.2 mL of 2% cupric acetate solution. Using a reflux setup bring the mixture to a gentle boil for 60 minutes. Cool the solution to 50-60 °C and add 2 mL of cold water while stirring. Once crystallization of benzil is complete, collect the solid via vacuum filtration in a Hirsch funnel, and wash the crystals with water. Draw air through the crystals for 5-10 minutes. Weight the crude product.

compound

MW

mp/bp

°C

density g/mL

mg or mL

mmol

benzoin

212.24 g/mol

mp 134-136

(solid)

350 mg

1.649

acetic acid

60.05 g/mol

bp 116-117

1.049

1.0 mL

xxxx

NH4NO3

80.043 g/mol

mp 210

(solid)

160 mg

1.998

Cu(O2CCH3)2 -H2O

(2% solution)

199.6493 g/mol

xxxxx

(solid)

0.2 mL

xxxxx

Part 2 - Benzil

Amount of benzoin used    _____350_____ mg      _________?_________ moles

Isolated Yield                        _________.36______ grams ________?__________ moles

Theoretical Yield   ________?__________ grams __________?________ moles

Percent Yield      _________?_________ %

compound

MW

mp/bp

°C

density g/mL

mg or mL

mmol

benzoin

212.24 g/mol

mp 134-136

(solid)

350 mg

1.649

acetic acid

60.05 g/mol

bp 116-117

1.049

1.0 mL

xxxx

NH4NO3

80.043 g/mol

mp 210

(solid)

160 mg

1.998

Cu(O2CCH3)2 -H2O

(2% solution)

199.6493 g/mol

xxxxx

(solid)

0.2 mL

xxxxx

Explanation / Answer

Molecular weight of benzoin = 212.24 g/mol

Amount of benzoin used = 350 mg = 0.35 grams

Moles of benzoin used = 0.35 / 212.24

= 0.001649 moles

Isolated yield = 0.36 g

Moles = 0.36 / 212.24

= 0.001696 moles

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