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The K_sp of Ag_2CrO_4 is 9.0 times 10^12. What would be the solubility of this c

ID: 1051736 • Letter: T

Question

The K_sp of Ag_2CrO_4 is 9.0 times 10^12. What would be the solubility of this compound in a solution that was already 0.10 M in potassium chromate? To separate a solution containing 0.10 M silver and 0.10 M lead ions, as may be done in qualitative analysis separation schemes, a source of I' may be slowly added to the mixture of ions. Which will precipitate first: Agl (K_sp = 1.5 times 10^16) or Pbl_2 (K_sp = 1.4 times 10^-8)? Also, what would be the concentration of I' necessary to see that first precipitation? Show work. An ideal gas placed in one side of a container (like one shown in 10/31 lecture). Over time it will... expand to fill the entire container if it is heated. expand to fill the entire container. There are more microstates with that arrangement. expand to fill the entire container. Positional probability is less; therefore, the entropy has increased expand to fill the container if it is an exothermic process and the net result will show greater probability. Of the following, which would have a negative entropy change? A salt crystal dissolves in water. Dry ice (solid CO_2) sublimes at room temperature. Individual amino acids bond together to make a protein. Liquid gasoline combusts to form CO_2 and H_2 O gas molecules. At constant pressure, the following reaction 2NO_2(g) rightarrow N_2 O_4(g) is exothermic. The reaction (as written) is: always spontaneous. spontaneous at low temperatures, but not high temperatures. spontaneous at high temperatures, but not low temperatures. never spontaneous. cannot tell. One method that can increase the solubility of some salts is to form a soluble complex ion. Which statement best describes the reason behind this method's result? CuS has a K_sp of 8.5 times 10^45. The reaction for Cu^2+ (aq) + 4 NH_3 (aq) rightarrow Cu (NH_3)_4^2+ has an equilibrium constant of approximately 5.6 times 10^11. What would be the approximate molar solubility of CuS in a 1.0 M solution of NH_3? ~ 6.9 times 10^17 M ~ 9.2 times 10^-23 M ~4.8 times l0^-33 M This one seems too "complex".

Explanation / Answer

2)

K2CrO4 decomposes completely as
K2CrO4 ---> 2K+ + CrO42-
[CrO42-] = 0.10 M

Ag2CrO4 <----> 2Ag+ + CrO42-
2s 0.10

Ksp = [Ag+]^2 [CrO42-]
9.0*10^-12 = (2S)^2 * 0.10
4*S^2 = 9.0*10^-11
S = 4.74*10^-6 M
Answer: 4.74*10^-6 M

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