Each of two isolated populations is in Hardy-Weinberg equilibrium (HWE) and the

Question

Each of two isolated populations is in Hardy-Weinberg equilibrium (HWE) and the number of individuals in different genotype categories in the two populations is shown below:
Genotype AA Aa aa
Population 1 4 32 64
Population 2 64 32 4
A. If the populations merge to form a single population, calculate the allele and genotype frequencies in the population immediately after merger.
B. Use the Chi- square test to determine if the merged population is in HWE.
C. In class we found that a population of 50 Aa and 50 aa individuals is not in HWE. Would the population be in HWE after one generation of random mating?

Explanation / Answer

A) AA Aa aa
pop1 4 32 64
+
pop2 64 32 4
=new 68 64 68

B) p2 +2pq + q2 = hwe

p=(AA +1/2Aa)/total

q=(aa+1/2Aa)/total

frequencies must add up to one

p2 +2pq + q2 = hwe

.5^2 +2(.5^2) + .5^2 = 1

expectation is :

AA = p^2 * total = .5^2 * 200= 50

Aa= 2(pq)*total = 100

aa = q^2 * total = .5^2*200 = 50

C. should be 50AA, 100Aa, 50aa

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