In this question, you may assume that non-relativistic calculations are adequate
ID: 1053872 • Letter: I
Question
In this question, you may assume that non-relativistic calculations are adequate. Given your answers to at least three significant figures. Answers must be accurate to 1%. An electron has a wavelength of 5.6 times 10^-9 m. What is the momentum of the electron? 2.137756 times 10^-26 2.843215 times 10^-26 3.781476 times 10^-26 5.029363 times 10^-26 6.689053 times 10^-26 8.896441 times 10^-26 1.183227 times 10^-25 1.573691 times 10^-25 kg m/s What is the speed of the electron? __________ m/s What is the kinetic energy of the electron? ________ JExplanation / Answer
wavelength of electron = 5.6 x 10^ -9 m
we have formula wavelength lamda = h / p where h is plankc ocnstant , P is momentum
5.6 x 10^ -9 m = ( 6.625x10^-34 m/s) / ( p)
p = 1.183 x 10^ -25
2) we have fomula momentum p = m x v
where m = mas of electron = 9.1 x 10^ -31 kg
now 1.183 x 10^ -25 = 9.1 x 10^ -31 kg x v where v is speed of electron
v = 1.3 x 10^ 5 m/s
Kinetic energy of electron = 1/2 x m x v^2
= ( 1/2) x 9.1 x 10^ -31 kg x ( 1.3x10^5 m/s)^2
= 7.7 x 10^ -21 kgm^2 /s2
= 7.7 x 10^ -21 J ( since J = kgm2/s2)
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