FALL1 ± Calculating Equilibrium Constants Part A The equilibrium constant, K. of

Question

FALL1 ± Calculating Equilibrium Constants Part A The equilibrium constant, K. of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium Phosgene (carbonyl chloride), COClh, is an extremely toxic gas that is used in manufacturing certain dyos and plastics Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures For a gaseous reaction with the general form Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at 478 C. Al equilbrium, the concentrations were measured and the foilowing results obtained the Ke and Kp expressions are given by Gas Partial Pressure co Cla (atm) 0880 1.20 COCh0240 The subscript c or p indicates whether K is expressed in terms of concentrations or pressures. Equilibrium- constant expressions do not include a term for any pure solids or liquids that may be involved since their compostion does not change throughout the reaction The standard state of a pure substance is the pure substance itself, and although the quantity may change the sample remain pure. The concentration is effectively equal to 1, and will not impact the magnitude of K What is the equilibrium constant, Kpof this eaction? Express your answer mamerically. My Answers GiveUp Review Part 6

Explanation / Answer

A) CO(g) + Cl2 (g) ---------------> COCl2 (g)

Kp = PCOCl2 / PCO PCl2 P = Partial pressure

= 0.24 / (0.88) (1.2)

= 0.227

Kp = 0.227

B)

H2 + I2 <----------> 2 HI

Initial 3.7 M 2.9 M 0

at equilibrium 3.7 -x 2.9-x 2x

Hence,

Equilibrium concentration of I2 = 2.9-x

But, given that  Equilibrium concentration of I2 = 0.02 M

Then, 2.9-x = 0.02

x = 2.88 M

Hence, equilibrium concentrations are

[H2]= 3.7 -x = 3.7 - 2.88 = 0.82 M

[I2]= 0.02 M

[HI] = 2 x = 2 (2.88 M) = 5.76 M

Hence,

Kc = [HI]2/[H2][I2]

=  [5.76]2/[0.82][0.02]

= 2023

Therefore,

Kc = 2023

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