V. Concentration Cell Copper - Copper Cu(s), CuCl2 (0.01 ) || Cu (s), CuCl2 (1.0
ID: 1055624 • Letter: V
Question
V. Concentration Cell
Copper - Copper
Cu(s), CuCl2 (0.01) || Cu(s), CuCl2 (1.0 M)
4. Calculate E°cell of this electrochemical cell. (include units)
E°cell _______0.00___________________
5. Calculate the reaction quotient (Q) of this reaction.
Q ___0.01___________________
6. Calculate the expected Ecell for this reaction.
Ecell ___0.0592___________________
7. Record the value of the measured Ecell
Ecell ____53.4______________
8. Calculate the percent error
% error __________________
The answers in bold are what I calculated but I'm confused because my measured value is so large and leaves a percent error of about 90100%! Am I doing something wrong or was there just error in my measured Ecell?
Explanation / Answer
E°cell = 0 by definition
Q = [Cu+2]/[Cu+2]
Q = 0.01/1 = 0.01
so
Ecell = E°cell - 0.0592/n*log(Q)
Ecell = 0 - 0.0592/2*log(0.01) = 0.0592 V
Q7
most likely... you mearued the volatage in mili volts... so 53.4 mvolts --> 53.4*10^-3 volts = 0.0534 V, which is what we expected
% error = real - measurea / real * 100% = (0.0592 -0.0534 -)/0.0592 * 100 = 9.79729% error!
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