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The value of k_ap for Ni(OH)_2(aq) is 6.0 times 10^lb. What is the molar concent

ID: 1055683 • Letter: T

Question

The value of k_ap for Ni(OH)_2(aq) is 6.0 times 10^lb. What is the molar concentration of nickel long in a saturated pH-7.0 buffer solution? Assume the buffer is sufficiently strong that the pH does not change during equilibration. Consider the reaction: NiCO_2(s) + 6 NH_3(aq) [Ni(NH_3)_2]CO_3(aq) Use the information below to determine the equilibrium constant for the reaction above. I) NH_3(aq) + H^+(aq) NH_4^+(aq) k_1 = 1.8 times 10^-5 II) Ni^2+(aq) + 6 NH_3(aq) [JNi(NH_3)_6]^2+(aq) k_1 = 5.6 times 10^4 III) NiCO_3(s) MoCO_3(aq) k_m = 6.6 times 10^4

Explanation / Answer

pH = 7

so

pOH = 14-7 = 7

[OH-] = 10^-7

so

Ni(OH)2 <-> Ni+2 + 2OH-

Ksp = [Ni+2][OH-]^2

6*10^-16 = [Ni+2](10^-7)^2

[Ni+2] = (6*10^-16)/(10^-7)^2 = 0.06 M

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