Why is phosphoric acid preferred for the conversion of cyclohexanol to cyclohexa

Question

Why is phosphoric acid preferred for the conversion of cyclohexanol to cyclohexane? In the formation of 1-bromobutane the leaving group attacks from the right side of the leaving group from the left side of the leaving group from the front side of the leaving group from the back side of the leaving group The conversion of cyclohexanol to cyclohexene oxidation reaction dehydration reaction substitution reaction addition reaction The elimination reaction of cyclohexanol results in formation of a sigma bond formation of one sigma bond and one pi bond formation of a only pi bonds presence of only sigma bonds In order to obtain larger yields one has to study the kinetics of the reaction apply principles of first law of thermodynamics apply concept of entropy apply concept of entropy apply concept of lessthanorequalto Chateleir's principle

Explanation / Answer

6) Phosphoric acid is protonating agent which protonated -OH group of cyclohexanol & convert it in to good leaving group that is water.

7) d) From bachside of leaving group. Since the attack of nucleophile & leaving of leaving group are the simultenious processes which involves SN2 type mechanism.

8) a ) Oxidation reaction. The removal of hydrogen or addition of oxygen is called as Oxidation. In this reaction removal of hydrogen takes place. Therefore this is an oxidation reaction.

9) c) Formation of only pi bond. The single bond between C-C is sigma bond. The newly forms a double bond due to formation of new pi bond.

10)e ) Apply concept of Lechateliers principle. From this principle we know that How many moles of reactant,what is the pressure, temp used to carryout reaction in forward direction.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.