Temperature of 50 mL of 2.0 M HCI before muting: T_i = ___________ degree C Temp

Question

Temperature of 50 mL of 2.0 M HCI before muting: T_i = ___________ degree C Temperature of 50 mL of 2.0 M NaOH before muting: T_i = _____________ degree C Temperature of 100 mL of solution after mixing: T_m = _________ degree C Assume that the density (1.00 g/ml) and specific heat of the solution (4.184J/g- degree C) are the same as pure water. The heat gained by the solution is; q_ solution = (mass, g)(4.184 J/g- degree C)(T_m - T_i) ___________ J Calculation Using the heat capacity of the calorimeter in part 1., the heat gained by the calorimeter is: q_calorimeter = (heat capacity)(T_m -T_i) ___________J Calculation The total heat of neutralization, delta H = -(q_solution + q_calorimeter) _____________J Calculation Moles of acid reacted _________ mole Calculation Moles of water produced _________ mole Calculation Calculate delta H of neutralization per one mole of water formed ___________ kJ/mole Calculation

Explanation / Answer

Q7

moles of acid =MV = (50*10^-3)(2) = 0.1 mol of acid

Q8

mole of water produce:

ratio is 1:1 so mol of water is also 1- --> 0.1mol of water formed

Q9

HRxn = -Q/n = 3400.65/0.1 = 34.00 kJ/mol

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