Determine the rate of glucose consumption by using the following equation and th

Question

Determine the rate of glucose consumption by using the following equation and the moles of glucose determined in a previous question. The molecular weight of glucose is 180.2 g/mole. f=1000 mw/t where f is the mg of sugar fermented per minute, m is the number of moles of sugar consumed, w is the molecular weight of the sugar in g/mole, and is the respiration time in minutes. Record your results for use in a later question. As measured volumes will vary slightly, pick the answer that is closest to yours. 0.1544 mg glucose/min 15.44 mg glucose/min 4.756 mg glucose/min 1.544 mg glucose/min

Explanation / Answer

Let the number of moles of glucose (as determined by you in previous experiment) = m

Mass of glucose = number of moles x molecular mass = (m x w) gram

                        = (mw) x 1000 mg = (1000 mw) mg       [Thus, 1000 mw is just the mass of glucose present in solution in milligrams. In short, the formula gives you the rate of consumption of glucose per unit time.]

We have,

            Number of moles of glucose = m

If the amount of glucose is provided in ‘gram’, convert it into moles using the formula-    

number of moles = (mass of glucose / molecular mass of glucose)

            w = 180.2 g mol-1

            t = t minute

Now,

            f = [1000 x m x (180.20)] / t = 1.802 x 105 m / t

Put the values of m and t in above equation to get exact value of f in milligram/ minute.

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