A. Standardization of a Sodium Hydroxide Solution Calculate the approximate mass

Question

A. Standardization of a Sodium Hydroxide Solution Calculate the approximate mass of NaOH required to prepare 500 mL ofa o 15 M NaoH solution Part A.2). olNaou Molarity x ers solunsn Calculate the approximate mass of K for the standardization of the NaoH solution Part A-3) Mass 204.23 Trial 3 Trial 2 Trial 1 1. Tared mass of KHC,H40, Gg) 204.23 g/mol 2. Molar mass of KHCsH4o. 3. Moles of KHC H40, (mo) Titration apparatus approval 4. Buret reading of NaoH, initial (mb) 5. Buret reading of NaoH final (ml) 6. Volume of NaOH dispensed (mL) 7. Molar concentration of NaoH (movi 3/6 L12uac 1222 2 2 2 Data Analysis, s. Average molar concentration of NaoH (molu) e 2 Data Analysis, Standard deviation of molar concentration Relative standard deviation of molar concentration (%RSD) Data Analysis, Experiment 9 14

Explanation / Answer

A. Molar mass of NaOH is 23+16+1= 40 and it is a monoacidic base.

So, 40 g of NaOH is required to prepare 1l of 1M NaOH solution.

To prepare 500 ml of 0.15M NaOH solution, NaOH required is

40X0.15X0.5 = 3g.

KHC8H4O4 is Potassaium hydrogen phthalate.It is a monobasic acid.

Molecular mass is 39+1+12X8+1X4+16X4 = 204(approx)

We know same equivqlent amount of acid neutralises same equivalent amount of base

Now, 3 g NaOH = 3/40 gm-equivqlent

So. 3/40 gm-equivqlent amount of acid is required, i,e., 204X3/40 = 15.3 g (approx) of the acid is required.

B. HA+NaOH = NaA +H2O

H2A + 2NaOH = Na2A + 2H2O.

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