sec M 0 0.0258 0.2 0.0207 0.4 0.0168 0.6 0.0134 0.8 0.0102 1 0.0084 1.2 0.0068 1
ID: 1058445 • Letter: S
Question
sec M
0 0.0258
0.2 0.0207
0.4 0.0168
0.6 0.0134
0.8 0.0102
1 0.0084
1.2 0.0068
1.4 0.0056
1.6 0.0039
1.8 0.0042
2 0.0020
2.2 0.0026
2.4 0.0013
2.6 0.0021
2.8 0.0010
3 0.0007
which was obtained for a reaction A P.
The first column contains time in seconds and the second column the concentration of reactant in molar units
The order of the reaction is in 1st order.
1) What is the rate constant of the reaction? Be sure you include units. Use "M" for molar and "s" for seconds
2) What is the rate of the reaction at t = 0.5s? Express your answer in units of M/s
3) What is the concentration of product at t = 0.5s?
Explanation / Answer
for a 1st order reaction , -rA=-dCA/dt = KCA
K= rate constant when integrated lnCA= lnCAO-Kt
where CA = concentration at any time, t and CAO= initial concenntration
so a plot of lnCA vs t gives the slope -K and intercept of ln CAO. the plot is shown below
the rate const K= 1.146/sec
the expression ln CA= -1.146t-3.633
CA= 0.0264*e(-1.146t) , dCA/dt= rate = -0.0264*exp(-1.146t)*1.146 at t=0.5s, rate = -0.017058M/s
at t=0.5 SS, lnCA= -1.146*0.5-3.633, CA=0.0149M
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.