Use the References to access Important values is needed for this question. The f
ID: 1058550 • Letter: U
Question
Use the References to access Important values is needed for this question. The following information is given for mercury at 1atm: boiling point = 356.6 degree C delta H_vap(356.6 degree C) = 295.6 J/g melting point = -39.00 degree C delta H_fus(-39.00 degree C) = 11.60 J/g specific heat solid = 0.1410 J/g degree C specific heat liquid = 0.1390 J/g degree C A 49.50 g sample of solid mercury is initially at -58.00 degree C. If the sample is heated at constant pressure (P = 1 atm), heat are needed to raise the temperature of the sample to 11.00 degree C.Explanation / Answer
Q= ms*Cs*delta Ts + ms*Hfus + ml*Cl*delta Tl
= 49.50*0.1410*(-39 + 58) + 49.50*11.60 + 49.50*0.1390*(11 + 39)
= 132.61 + 574.2 + 344.03
= 1050.84 J
= 1.051 KJ
Answer: 1.051 KJ
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