Question 3 a) The process of breathing maintains the concentration of oxygen in
ID: 1058850 • Letter: Q
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Question 3 a) The process of breathing maintains the concentration of oxygen in human blood in the lungs at 1.6 x 10 mol of oxygen per dm of blood. Oxygen reacts in blood with a compound, haemoglobin (represented below as Hb) to yield oxyhaemoglobin,(Hbon): Hb O Hbo. The reaction follows first order kinetics with respect to each of the reactant. The lung processes keep the haemoglobin concentration constant in the lungs at 8.0x 104 mol of haemoglobin per dm' of blood. The rate constant for the reaction is 2.1 x 106 dms mol is at body temperature. Calculate the rate of formation of oxyhaemoglobin per dm3 of blood. i) the rate of consumption of oxygen per dm3 of blood iii) In certain illness it is necessary that the rate of formation of oxyhaemoglobin should be increased to 1.1 x 10 mol dm3 s I. Since the haemoglobin concentration remains constant, to what value must the oxygen concentration be changed in order to achieve this raised rate of oxyhaemoglobin formation?Explanation / Answer
a)Rate of HbO2 formation, rHbO2= K[Hb][O2]
= 2.1*106* 8*10-6* 1.6*10-6 = 26.88*10-6 moles/dm3 of blood.
b) rHbO2= -rO2= -26.88*10-6 moles/dm3
c) 1.1*10-4 = 2.1*106*8*10-6*[O2]
[O2] = 1.1*10-4/ (2.1*106*8*10-6) =6.56*10-6 moles/dm3 of blood
b) ln (K2/K1)= (Ea/R)*(1/T1-1/T2)
K1= 4.8 min and K2= 4.5 min and T1= 91.2+273.15 and T2= 100+273.15
ln (4.8/4.5) = (Ea/R)*(1/364.35- 1/373.15)
Ea= activatino energy = 8290 joules/mole
c) the reaction is SO2Cl2(g) -------> SO2(g)+ Cl2(g)
KP= 2.18= [SO2][CL2]/[SO2Cl2]
initially PSO2Cl2= 9 atm
let P= drop in pressure of SO2Cl2 to reach equilibrium
So at equilibrium PSO2Cl2= 9-P, PSO2= PCl2= P
P indicates the partial pressure
Kp =2.18-= P2/(9-P) when solved using excel, P= 2.17
So at equilibrium PSO2Cl2= 9-2.17= 6.83, PSO2= PCl2= 2.17 atm
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