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suppose 10.0 mL of the solution in the previous question was extracted with 10 m

ID: 1059256 • Letter: S

Question

suppose 10.0 mL of the solution in the previous question was extracted with 10 mL of methylene chloride. After extraction, the aqueous layer gave an absorbance of 0.37. Using the graph above, A) estimate the concentration of I2 in the aqueous layer, B) then calculate the concentration of I2 in the methylene chloride layer, then C) calculate the Kd.


in this lab? A solution that was 0.002 M absorbance of0.84 units on an arbitrary scale. The aqueous olution by itself was used a the control blank and setto an on the same scale. Draw up a graph of Iz concentration (the independent variable) against absorbance (the dependent variable) assuming the relationship is linear using the tained for the grid below. lecular iodine hloride or in xplain. to form the erefore much 1 a greater suppose 100 ml. of the solution in the previous question was extracted with 10 mL of or methylene chloride. After extraction. the aqueous layer gave an absorbance of 0.37 Using the graph you drew in question above, a) estimate the concentration of in the aqueous layer, by then calculate the of la in the methylene layer, and then c) calculate the Ka (Show calculations on a separate page.)

Explanation / Answer

a ) From the graph , concentration of I2 in aqueous layer = 8.80952*10-4 M
b) concentration of solute before extraction in aqueous layer is equal to sum of the concentrations of solute
in aqueous and organic layers after extraction.
   Saq ( before extraction) = Saq(after extraction) + Sorg (after extraction)
0.002 mol/lit = 8.80952*10-4 mol/lit + Sorg
   Sorg = 1.11904 * 10-3 mol/lit or M
Therefore concentration of I2 in methylene chloride layer =  1.11904 * 10-3 M
c) Kd = [I2]organic / [I2]aqueous = 1.11904 * 10-3 / 8.80952*10-4 M = 1.27026