84 Kr is among the most tightly bound of all nuclides. It is more than 55% of na

Question

84Kr is among the most tightly bound of all nuclides. It is more than 55% of natural krypton. Note that 84Kr has even numbers of both protons and neutrons. Calculate BE/A, the binding energy per nucleon for 84Kr in MeV/nucleon. (Assume 1 u = 931.5 MeV/c2. Give your answer to at least three decimal places.)

BE Kr is among the most tightly bound of a nuclides. It is more than 55% of natural krypton. Note that Kr has even numbers of both protons and neutrons. Calculate the binding energy per nucleon, for 84 Kr in Mev/nucleon. (Assume 1 u 931.5 Mev/c2. Give your answer to at least three decimal places. MeV/nucleon Compare your result with the approximate va e obtained from the graph n the figure below BEA Te Sm 7.6 238 7 111B 5 8 4 2 150 200 100 Atomic mass

Explanation / Answer

Kr-84 has 36 proton and 48 neutron

mass = 36 x 1.00727647 + 48 x 1.00866492 = 84.67786908 u

mass defect of Kr-84 = 84.67786908 - 84 = 0.67786908 u

Binding energy = 0.67786908 x 931.5 = 631.435 MeV

Binding energy per nucelon = 631.435/84 = 7.517 MeV/nucleon

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