First launch this video. During the video, you\'ll be asked a conceptual questio
ID: 1060512 • Letter: F
Question
First launch this video. During the video, you'll be asked a conceptual question about the example. After watching the video, answer the related questions at the right. You can watch the video again at any point. Consider the following reaction at 298 K: H_2 S(g) + SO_2(g) rightarrow 3S(s, rhombic) + 2H_2 O (g), delta G degree _rxn = -102 kJ Calculate delta G_rxn under these conditions: P_H_2 S = 2.00 atm P_SO_2 = 1.50 atm P_H_2 O = 0.0100 atm Express the free energy change in kilojoules to three significant figures.Explanation / Answer
DGrxn = DG0rxn + RTlnK
k = pH2O^2/(pH2S*pSO2)
R = 8.314 j.k-1mol-1
T = 298 k
DG0 = -102 kj = -102*10^3 joule
DGrxn = DG0rxn + RTln[pH2O^2/(pH2S*pSO2)]
= (-102) + 8.314*10^-3*298ln(0.01^2/(2*1.5))
= -127.541 kj
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