Help Please!!!! 1. How many moles of gas must be forced into a 4.4 L tire to giv

Question

Help Please!!!!

1. How many moles of gas must be forced into a 4.4 L tire to give it a gauge pressure of 31.6 psi at 30 C?

The gauge pressure is relative to atmospheric pressure. Assume that atmospheric pressure is 14.8 psi so that the total pressure in the tire is 46.4 psi . Express your answer using two significant figures.

2. Part A

A sample of ideal gas at room temperature occupies a volume of 31.0 L at a pressure of 602 torr . If the pressure changes to 3010 torr , with no change in the temperature or moles of gas, what is the new volume, V2? Express your answer with the appropriate units.

Part B If the volume of the original sample in Part A (P1 = 602 torr , V1 = 31.0 L ) changes to 72.0 L , without a change in the temperature or moles of gas molecules, what is the new pressure, P2? Express your answer with the appropriate units.

3.. A scuba diver with a lung capacity of 5.2 L inhales a lungful of air at a depth of 50 m and a pressure of 6.0 atm . If the diver were to ascend to the surface (where the pressure is 1.0 atm) while holding her breath, to what volume would the air in her lungs expand? (Assume constant temperature.) Express your answer using two significant figures.

Explanation / Answer

1) Apply the Ideal Gas Law to the air inside the tire :
---------------------------------------...

( P ) ( V ) = ( n ) ( R ) ( T )

n = ( P ) ( V ) / ( R ) ( T )

P = Pgauge + Pbaro = 31.6 psig + 14.8 psia = 46.4 psia

P = ( 46.4 psia ) ( 1 atm / 14.696 psia ) = 3.15 atm

n = ( P ) ( V ) / ( R ) ( T )

n = ( 3.15 atm ) ( 4.4 L ) / ( 0.08206 atm - L / mol - K ) ( 30.0 + 273.2 K )

n = 0.5574 moles <--------------------------

m = ( n ) ( M )

m = ( 0.5574 mol ) ( 28.96 g/mol ) = 16.14 g <-------------------------

The amount of air to be put into the tire is quite small, but very significant for tire
to be properly inflated.

2)  a) p1v1= p2v2
602 x 31.0= 3010 x v2
v2= 6.2 L

b) 602 x 31 = p2 x 72.0
p2= 259.19 torr

3) P1V1 = P2V2

5.5 atm * 6 L = 1 atm * x L

x = 33

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.