an insulated container is used to hold 41.60 An insulated container is used to h
ID: 1061047 • Letter: A
Question
an insulated container is used to hold 41.60 An insulated container is used to hold 41.60 g of water at 26.20 degree C. A sample of copper weighing 8.40 g is placed ¡n a dry test tube and heated for 30 minutes in a boiling water bath at 100.10 degree C. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is 0.385 J/(g middot degree C), calculate the maximum temperature of the water in the insulated container after the copper metal is added.Explanation / Answer
heat lost by hot copper = heat gained by cold water
Heat gained by hot water = specific heat of water x mass of water x temperature change
= 4.184 J/gC x 41.6 g x ( T-26.2) C where T is final temp of solution
= 174.0544 T - 4560.2253 ............(1)
Heat lost by hot copper = specific heat of copper x mass of copper x temperature change
= 0.385 J/gC x 8.4 g x (100.1 -T)
= 323.7234 - 3.234 T ...........(2)
equating (1) and (2) we get
174.0544T - 4560.223 = 323.7234 - 3.234T
177.2884 T = 4883.9464
T = 27.55 C is final temperature of solution
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