1-propanol (p*_1 = 20.9 torr at 25 degree C) and 2-propanol (p*_2 = 45.2 torr at
ID: 1062253 • Letter: 1
Question
1-propanol (p*_1 = 20.9 torr at 25 degree C) and 2-propanol (p*_2 = 45.2 torr at 25 degree C) form ideal solutions in all proportions. Let x_1 and x_2 represent the mole fractions of 1-propanol and 2-propanol, respectively, in a liquid mixture and y_1 and y_2 represent the mole fractions of each in the vapor phase For a solution of these liquids with x_1 = 0.270, calculate the composition of the vapor phase at 25 degree C if the vapor above the liquid phase is composed only of 1-propanol and 2-propanol.Explanation / Answer
y1 = po1*x1
= 20.9*0.270
= 5.64 torr
y2 = po2*x2
y2 = po2*(1-x1)
= 45.2*(1-0.270)
= 33.0 torr
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