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EXPERIMENT 13: DETERMINATION o THE MASS OF MAGNESIUM METAL IN A SAMPLE Instructo

ID: 1062385 • Letter: E

Question

EXPERIMENT 13: DETERMINATION o THE MASS OF MAGNESIUM METAL IN A SAMPLE Instructor: Section/Group: Post-Lab Report (Use the In-lab observat to complete the laboratory report. Turn in to your ions Instructor when you have completed the report) Sample 2 Sample 1 ID of sample Buret reading of vol, of Ha collected T.Ba unL ml. vol of Hain graduated portion of buret Sb.0 mL 50.0 mL Volume of buret below 50-mL mark la ml. 5 ml. 1.3 T IS, 14 Total volume of H, collected 17 mL, Barometric pressure 300xa5.Y mrhn Tea torr Difference in water levels omm Correction for difference in water levels Pressure o 1153 Temperature of water bath Water vapor pressure at water bath temp. Volume H, corrected to STP ml, ml. Moles He collected mol Mass Mg in sample Show your work for the determination of the volume of gas collected for include calculation of volume inside the graduated portion of the buret from buret reading and use of void volume. Experim st ul Determination of the Mass of Ma.nesium Metal in a sample 193

Explanation / Answer

Using the relation P1V1/T1=PoVo/To

Sample 1 = Vo =12.49mL(V1=13,44mL; P1=762Torr T1=294.5 ; Po=760 Torr To=273K)

Sample 2 =Vo= 14.60ml (V1=15.74mL; P1=762Torr T1=295K ; Po=760 Torr To=273K)

Sample 1 moles of H2= 0.01249/22,4L=5.578X10^-4mol

Sample 2 moles of H2= 0.0146l/22.4L=6,52X10^-4mol

Mass of Mg sample1= 24 g/molX 5.578X10^-4mol=0.0134g

Mass of Mg sample 2=24g/mol X6.52X10^-4mol= 0.0156g

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