In special experiment: Buffers, two different buffer systems were examined, made

Question

In special experiment: Buffers, two different buffer systems were examined, made from stock solution of NaH_2PO_4 with the same molar concentration. Buffer 1: 12mL of NaH_2PO_4 and 8mL of Na_2HPO_4 Buffer 2: 8mL of NaH_2PO_4 and 12mL of Na_2HPO_4 Which of the following explanations is the best for why Buffer 1 handled the addition of a basic solution better than buffer 2? Buffer 1 has a lower starting pH and will have a lower buffer capacity than Buffer 2 Buffer 1 has a lower starting pH and will have a higher buffer capacity than Buffer 2. Buffer 1 has a higher starting pH and will have a lower buffer capacity than Buffer 2. Buffer 1 has a higher starting pH and will have a higher buffer capacity than Buffer 2.

Explanation / Answer

pH =pka2 + log [ Na2HPO4] / [ NaH2PO4]

For 1st buffer

pH = pKa2 + log 8/12

pH = pKa2 - 0.176

For 2nd buffer

pH = pKa2 + log 12/8

pH = pKa2 + 0.176

SO buffer 1 has lower starting pH and will have higher buffer capacity than buffer 2

It is very simple

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