e 74 and the Electronic Structure of Atoms wavelength of a (in nanometers) emitt
ID: 1063244 • Letter: E
Question
e 74 and the Electronic Structure of Atoms wavelength of a (in nanometers) emitted during a transition fro e to the 2 state in the hydrogen atom? can We are given the initial and final states in the (7.6. Then from Equation emission process. We e energy of the emitted photon using Equation co e can solve for the wavelength of the photon. The value of Rydberg s he text. rom Equation (7.6) we write AE 2.18 x 10 52 22 4.58 x 10 J sign indicates that this is energy associated with an emission pro wavelength, we will the minus for AE because the wav must be positive. Because AE hv or v AEh, we can calcu the photon by writingExplanation / Answer
From Rydburg's Equation , 1/ = R[(1/ni2) – (1/nf2)]
Where R = Rydburg's constant = 10.96 x106 m-1
= wavelength = ?
ni = 2
nf = 3
Plug the values we get
1/ = 10.96 x106[(1/22) – (1/3f2)]
= 1.52x106
= 6.569x10-7 m
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