REPORT SHEET EXPERIMENT Titration of Acids and Bases 20 A. Standardization of So

Question

REPORT SHEET EXPERIMENT Titration of Acids and Bases 20 A. Standardization of Sodium Hydroxide (NaoH) Solution Trial Trial 2 Trial 3 Mass of bottle KHP Mass of bottle Mass of KHP used waxp aper Final buret reading Initial buret reading mL of NaOH used Molarity of NaOH Standard deviation Average molarity Show your calculations for molarity and standard deviation. B. Analysis of an Unknown Acid Trial 1 Mass of bottle unknown Mass of bottle Mass of unknown used 10.0m/ Final buret reading Initial buret reading ml of NaOH used Mass of KHP in unknown Percent of KHP in unknown Copyright c 2012 Pearson Education, loc

Explanation / Answer

KHP + NAOH = H2O + NaKP

mol of KHP = mass/MW = 0.379/204.22 = 0.0018558 mol of KHP

mol of base= mol of KHP = 0.0018558 mol

so..

[NaOH] = mol of NaOH / V = 0.0018558/(18.90*10^-3) = 0.09819 M of NaOH

b)

mol of KHP = mol*V = 0.09819*8.3*10^-3 = 0.000814977 mol

mass o fKHP = mol*MW = 0.000814977*204.22 = 0.166 g of KHP

then

% KHP = 0.166 /0.463*100 = 35.853%

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.