Mass of metal (g) Temperature of metal (boiling water) (degree C) Mass of calori

Question

Mass of metal (g) Temperature of metal (boiling water) (degree C) Mass of calorimeter (g) Mass of calorimeter + water (g) Mass of water (g) Temperature of water in calorimeter (degree C) Maximum temperature of metal and water from graph (degree C) Instructor's approval of graph Calculations for Specific Heat of a Metal Temperature change of water, Delta T(degree C) Heat gained by water (J) Temperature change of metal, Delta T (degree C) Specific heat of metal, equation 25.5 (j/g degree C) Average specific heat of metal (J/g middot degree C)

Explanation / Answer

Mass of water = 26.266 g - 6.7 g == 19.566 g

Temperature change in water = 25.2 oC - 21.5 oC

= 3.7 oC

Heat gained by water = Q = 19.566 g x 4.18 J/g oC x 3.7 oC

= 302.61 J

Temperature change in metal = 91 oC - 21.5 oC

= 69.5 oC

Specific heat of metal == 302.61 J / (56.30 g x 69.5 oC )

= 0.077 J/g oC

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