Initial rate data were obtained for the following reaction: 2A + B rightarrow C

Question

Initial rate data were obtained for the following reaction: 2A + B rightarrow C + D Expt [A], M [B], M Rate, M/s 1. 0.20 0.10 2.2 times 10^-5 2. 0.40 0.10 4.4 times 10^-5 3. 0.20 0.20 8.8 times 10^-5 What is the rate law for the reaction? rate = k[A] rate = k[A]^2[B]^2 rate = k[A][B]^2 rate = k[A][B] Which of the following is a true statement about chemical equilibrium in general At equilibrium the total concentration of products equals the total concentration reactants, that is, [products] = [reactants]. Equilibrium is the result of the cessation of all chemical change. There is only one set of equilibrium concentrations that equals the K_c value. At equilibrium, the rate of the forward reaction is equal to as the rate of the reaction.

Explanation / Answer

rate = K [A]x [B]y

rate1 / rate3 = k1[A1]x[B1]y / k3[A3]x[B3]y

k's will cancel and [A] will cancel

rate1 / rate3 = [B1]y / [B3]y

(2.2x10-5 / 8.8x10-5) = (0.1)y / (0.2)y

0.25 = 0.1y / 0.2y

0.25 = 0.5y

y = 2

similarly ...

rate1 / rate2 = k1[A1]x[B1]y / k2[A2]x[B2]y

k's will cancel and [B] will cancel

rate1 / rate2 = [A1]x / [A2]x

(2.2x10-5 / 4.4x10-5) = (0.2)x / (0.4)x

0.5 = 0.2x / 0.4x

0.5 = 0.5x

x = 1

so rate expression will be

rate = k [A] [B]2

14)

The concentrations of reactants and products remain constant.
True - Equilibrium is established when neither the products nor the reactants change in concentration

The rates of the forward and reverse reactions are equal.
True

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.