2H^+(aq) + Fe(s) rightarrow H_2(g) + Fe^2+ (aq) Pt(s)|H_2(g)|H^+ (aq)||Fe^2+ (aq

Question

2H^+(aq) + Fe(s) rightarrow H_2(g) + Fe^2+ (aq) Pt(s)|H_2(g)|H^+ (aq)||Fe^2+ (aq)|Fe(s) Fe^2+ (aq)|Fe(s)||H_2(g)|H^+ (aq)|Pt(s) Pt(s)|H^+ (aq)|H_2(g)||Fe(s)|Fe^2+ (aq) Fe(s)|Fe^2+ (aq)||H^+ (aq)|H_2(g)|Pt(s) 2NO_3^- (aq) + 8H^+ (aq) + 3Cu(s) rightarrow 2NO(g) + 4H_2O(l) + 3Cu^2+ (aq) Pt(s)|NO_3^- (aq), H^+ (aq), H_2O(l)|NO(g)||Cu(s)|Cu^2+ (aq) Pt(s)|NO(g)|NO_3^- (aq), H^+ (aq), H_2O(l)||Cu^2+ (aq)|Cu(s) Cu^2+ (aq)|Cu(s)||NO(g)|NO_3^- (aq), H^+ (aq), H_2O(l)|Pt(s) Cu(s)|Cu^2+ (aq)||NO_3^- (aq), H^+ (aq), H_2O(l)|NO(g)|Pt(s)

Explanation / Answer

b)

The notation goes as follows:

[oxidation] // [reduction]

so

2H+ --> H2 this is reducing

Fe(s) -> Fe+2 this is oxidizing

Fe(s) / Fe+2(aq) // 2H+ / H2(g) must be the equation

the pt elecrode must be stated in the right side so

Fe(s) / Fe+2(aq) // 2H+ / H2(g) / Pt(s)

c)

Cu is being oxidized, so it goes in the left side

ignore a and b then

form c and d

ignore C since it has aqeous Cu+2 initially, this is false since Copper is solid initially

so

choose D

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