Trial Trial Trial 1 1. Mass of Mg consumed, g 3 2.96 x lord 2. Moles of Mg consu

Question

Trial Trial Trial 1 1. Mass of Mg consumed, g 3 2.96 x lord 2. Moles of Mg consumed, n 0.0474 3. Initial eudiometer volume, mL sl 4. Final eudiometer volume, ml. Q. o U L 8334 5. Volume of gas, L 6. Temperature, CIK -210 7. Barometric Pressure, mmHg Tio nNHg 710m 8. Vapor pressure of water, mmHg 2 teEr 0.7ol an 9. Partial pressure H2, mmHglatm o.2ol atm 5fn 0, 80% nel 10. Rexperimental L atm/ mol K. 0807 11. Average Experimental R value 003 voos 12. Average 000 Deviation from the 13. Average Deviation 14 Average Deviation 0221 15. Error IRexp Ruheel 16 Relative Error Instructor Grade on Accuracy Instructor Grade on Precision (0-3 Points) (0-3 Points) Sample Calculation: (Attach sheets as needed)

Explanation / Answer

1. Effect of calculate R value due to following,

(a) If Mg strip is coated with MgO layer, moles of Mg reacting is less. It would generate less H2 gas and thus moles of H2 formed would be less. R is inversely related to moles, thus R vaue would be higher in this case than actual value.

(b) If the pressure is not equlibriated, the pressure of H2 woule be lower than actual value. R is directly related to pressure, so R value would decrease.

(c) If some Mg floated on top and did not react, molef of H2 would be lower, and thus, R value would be higher.

2. Limiting factor in the significant figure would be upto 5 digits.

3. If instead of H2 gas, HCl was generated in the experiment. The % error would be lower as each Mg disolved would produce 2 moles of HCl in the system and thus pressure equilibriation step errors could be avoided. Less chances of error, increases accuracy.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.