The energy of the transition in Mossbauer spectroscopy depends on the s electron

Question

The energy of the transition in Mossbauer spectroscopy depends on the s electron density at the nucleus. Fe(O) is s2d3. Fe(II) has lost these outer s electrons which decreases this density and has a significant an effect on the energy relative to Fe(O). Fe(III) loses a d electron, which changes the shielding, which has an effect on the inner s electrons, so that also should have an effect on the Mossbauer energy. Will the shift in energy of the Mossbauer transition in Fe(III) be larger or smaller than the shift of Fe(II), relative to Fe(O)? In some enzyme systems, Fe(IV) is proposed as a component. Could this be distinguished from other Fe states by its Mossbauer shift? Explain.

Explanation / Answer

Mossbauer is based on the electron density.   Fe(II) has higher electron density thus, it has hgiher mossbauer shift.

Fe(III) has lower mossbauer shift than Fe(II)

Fe(IV) can be distinguished from other states of Fe.    It has very low shift in mossbauer spectra

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