Gradebook O 12/5/2016 11:00 PM A 65.5/100 12/5/2016 12:50 PM Print Calculator i

Question

Gradebook O 12/5/2016 11:00 PM A 65.5/100 12/5/2016 12:50 PM Print Calculator i Periodic Table Question 13 of 27 Map AA Sapling Learning macmillan learning At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, KC. 3A(g) 2 Ble) 4C(g) 3.13 x 10 If, at this temperature, 2.10 mol of A and 3.70 mol of B are placed in a 1.00-L container, what are the concentrations of A, B, and C at equilibrium? Number M Number M Number M A Previous Give Up & View Solution Check Answer Next d Exit nt

Explanation / Answer

For

Kc = [products]/[reactans]

Kc = [C]^4 / [A]^3 [B]^2

so

initially:

[A] = 2.1

[B] = 3.7

[C] = 0

in equilibrium

[A] = 2.1 -3x

[B] = 3.7 -2x

[C] = 0 + 4x

so..

Kc = [C]^4 / [A]^3 [B]^2

3.13*10^19 = (4x)^4 / ( 2.1 -3x)^3 ( 3.7 -2x)^2

solve for x using excel:

sqrt(3.13*10^19) = (4x)^2 / (2.1-3x)^1-5 * (3.7-2x)

Since 10^19

assume most of it is C

then

x = 0.7

[A] = 2.1 -3*0.7 = 0

[B] = 3.7 -2*0.7 = 2.3

[C] = 0 + 4*0.7 = 2.8

approx

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