Electromagnetic radiation can be specified by its wavelength (lambda), its frequ

Question

Electromagnetic radiation can be specified by its wavelength (lambda), its frequency (v) or its period (tau). The period tau is the time is takes one complete wavelength to pass a point in space. Based on this information, what is the mathematical relationship between v and tau? A) c = tau times v B) tau = c/v C) v = tau D) tau = v/c E) v = 1/tau If the energy of a photon is 1.32 times 10^-18 J, what is its wavelength in nm? A) 1.99 times 10^15 nm B) 1.50 times 10^-7 nm C) 150. nm D) 1.99 times 10^24 nm E) none of the above Use the Rydberg equation to calculate the frequency of a photon absorbed when the hydrogen atom undergoes a transition from n_1 = 2 to n_2 = 4. (R = 1.096776 times 10^7 m^-1) A) 8.226 times 10^14 s^-1 B) 2.056 times 10^6 s^-1 C) 6.165 times 10^14 s^-1 D) 2.742 times 10^7 m^-1 E) > 10^15 s^-1 The size of an atomic orbital is associated with A) the angular momentum quantum number (l). B) the spin quantum number (m_s). C) the magnetic quantum number (m_1). D) the principal quantum number (n). E) the angular momentum and magnetic quantum numbers, together. Which of the following is a correct set of quantum numbers for an electron in a 3d orbital A) n = 3, l = 2, m_l = 3 B) n = 3, l = 1, m_l = +3 C) n = 3, l = 0, m_l = -1 D) n = 3, l = 2, m_l = -2 E) n = 3, l = 3, m_l = +2

Explanation / Answer

4)

E = hc/lambda

lambda = 6.62*10^-34*3*10^8/(1.32*10^(-18))

lambda = 1.5*10^-7 m = 150 nm

5)

The Rydberg Formula is this:

1/wavelength = R*((1/n1^2) - (1/n2^2))

So now you just input the values in for each.

1/wavelength = (1.0967776x10^7) * ((1/2^2)-(1/4^2))

1/wavelength = (1.0967776x10^7) * ((1/4)-(1/16))

1/wavelength = (1.0967776x10^7) * (3/16)

Frequency = c/wavelength = (1.0967776*10^7) * (3/16) * 3*10^8 = 6.16*10^14 s^-1

6)

D) the principal quantum numbre (n)

7)

correct option (D)

n=3, l=2, ml=-2

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