PLEASE EXPLAIN HOW!!!!! The following information is for the element cobalt at 1

Question

PLEASE EXPLAIN HOW!!!!!

The following information is for the element cobalt at 1 atm pressure

Boiling point= 3097 degrees C

Melting point= 1495 degrees C

Specific heat solid= 0.4180 J/g degrees C

Specific heat liquid= 0.6860 J/g degrees C

Delta H_vap (3097 degrees C)= 6603 J/g

Delta H_fus (1495 degrees C)= 262.7 J/g

A 1.00g sample of solid cobalt is initially at 1395 degrees C. If the sample is heated at a constant pressure (P=1atm), how much heat must be added to the sample to raise its temperature to 1595 degrees C?

A. 373 J

B. 263 J

C. 110 J

D. 6713 J

E. 305 J

Explanation / Answer

Heat = mass * specific heat * change in temperature

Heat = mass * specific heat * (t2-t1)

heat =1.00 * 0.4180 *(1595-1395) = 0.4180 (200) = 83.6 J

Therefore, heat added is 83.6 J

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