4. Using the Rydberg formula, calculate the initial energy level when an electro

Question

4. Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom 2 and emits a photon at 410.1 nm. Note: the Rydberg constant 1.097 x 107 m Answer! What is the maximum number of electrons that are allowed to have the following set of quantum numbers in one 4 and m +2 Answer n 3 and t 1 Answer: n 1 and m, Answer: 6. Provide the possible values for the other three quantum numbers for electrons in n-3. Possible Values Max, e 7. What are the four quantum numbers for the last electron in each following more negative to Note: orbital notation (Chapter 8) makes this easier. Assume that m values from more positive, and that a spin up e (m, +1 each fill an orbital before spin down e begin to pair

Explanation / Answer

4)
Use Rydberg formula:

1/lambda = R* (1/n1^2 - 1/n2^2)
1/(410.1*10^-9) = (1.097*10^7)*(1/2^2 - 1/n^2)
2.438*10^6 = (1.097*10^7)*(1/4 - 1/n^2)
(1/4 - 1/n^2) = 0.2223
n = 6

Answer: 6

5)
a)
n=4 and ml = +2 is allowed for l = 3 and 2 only
so there are two ml = +2 orbital form n=4
number of electron = number of orbital * 2 = 2*2 = 4
Answer: 4

b)
l=1 can have ml = -1,0,1
there are 3 orbitals
number of electrons = 6
Answer: 6

c)
n=1 can have l=0 and ml=0
ms = +1/2 means only 1 orbital
number of electrons = 2
Answer: 2

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