What would be the product of following reaction: CH_3CH_2Br + NaCN rightarrow CH

Question

What would be the product of following reaction: CH_3CH_2Br + NaCN rightarrow CH_3CH_2CN CH_3CH_2Na CH_3CH_2Na no reaction What is the predicted shape, bond angle, and hybridization for +CH_3? trigonal planar, 120 degree, sp^2 trigonal planar, 120 degree, sp^3 trigonal planar, 109.5 degree, sp^2 trigonal pyramidal, 120 degree, sp^2 trigonal pyramidal, 109.5 degree, sp^2 Which one is showing the relationship as constitutional Isomers? In a stable chair form of cis 1, 2 -Dimethylcyclohexane, two methyl groups are both equatorial both axial one axial and one equatorial cant tell For the reaction, which one is the right statement? CH_3COONa + CF_3COOH === CH_3COOH + CF_3COONa. Its K is greater than 1 CH_3COONa is more stable than CF_3COONa CH_3COOH is acid CH_3COONa is conjugate base

Explanation / Answer

25)
NaCN breaks into Na+ and -CN . negative charge in on C
It will be acting as nucleophile
Answer: a

26)
It is SP2 hybridised
hence it will be trigonal planar
bond angle for trigonal planar is 120 degree
Answer: A

27)
d is having same molecular formula but different connectivity
Answer: d

I am allowed to answer only 1 question at a time

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