what\'s the answer to 66? 12.66 A solution of 6.85 of a carbohydrate in 100.0 g

Question

what's the answer to 66?

12.66 A solution of 6.85 of a carbohydrate in 100.0 g of water has a g of 024 g/ml, and osmotic pressure density an mass of of 4.61 atm at 20.0 C, Calculate the molar the carbohydrate Colligative Properties of Elcctrolyte Solutions Review Questions 12,67 What are ion pairs? What ctfect does ion-pair for mation have on the colligative properties of a solu- tion? How does the ease of ion-pair formation depend on (a) charges on the ions, (b) size of the ions, (c) nature of the solvent (polar versus nonpo- lar), (d) concentration?

Explanation / Answer

m = 6.85 g of Carbhydrate

m = 100 g of water

D = 1.024 g/mL

Posm = 4.61 atm at T = 20°C = 293 K

find MW of carb

so...

Posm = M*R*T

M = mol/V

find molarity

mol = mass/MW = 6.85 / MW

V = m/D = 100/1.024 = 97.65 mL = 97.65*10^-3 L

M = (6.85)/(97.65*10^-3) 1 / MW = 70.1484 /MW

so

Posm = M*R*T

Posm = 70.1484 /MW*R*T

substitute data

4.61 = 70.1484 /MW *0.082*293

MW = 70.1484 *0.082*293/4.61

MW = 365.5 g /mol

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