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Express the equilibrium constant for the following reaction. 16 CH_3Cl (g) + 8 C

ID: 1068839 • Letter: E

Question

Express the equilibrium constant for the following reaction. 16 CH_3Cl (g) + 8 Clz (g) = 16 CH_2Cl_2 (g) + 8 H_2 (g) K = [CH_2Cl_2][H_2]/[CH_3Cl][Cl_2] K= (CH_3Cl][Cl_2]/[CH_2Cl_2][H_2] K=[CH_3Cl]^16[Cl_2]^8/[CH_2Cl_2]^16[H_2]^8 K=[CH_2Cl_2]^16[H_2]^8/[CH_3Cl]^16[Cl_2]^8 K=[CH_3Cl]^1/2[Cl_2]/[CH_2Cl_2]^1/2[H_2] Express the equilibrium constant for the following reaction. P_4O_10(s)= P_4(s) + 5 O_2(g) K= [P_4][O_2]^5/[P_4O_10] K= [P_4O_10]/[P_4][O_2]^5 K= [O_2]^5 K= [O_2]^5 K= [P_4O_10]/[P_4][O_2]^1/5 The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. A(g) + B(g)= AB(g) K_c = 0.24 AB(g) + A(g)= A_2B(g) K_c = 3.8 2 A(g) + B(g) = A_2B(g) K_c = ? 4.0 0.91 3.6

Explanation / Answer

23) 16 CH3Cl + 8Cl2 -------> 16 CH2Cl2 + 8H2

K = product / reactant

K = [CH2Cl2]16 [H2]8 / [CH3Cl]16 [Cl2]8

option D is correct

24) P4O10 ----->P4 + 5O2

K = [P4] [O2]5 / [P4O10]

option A is correct

25) K1 = [AB] / [A] [B] = 0.24

K2 = [A2B] / [AB] [A] = 3.8

K3 = [A2B] / [A]2 [B] = ?

in equation 2nd put the value of 1 equation

[A2B] [[AB]/[AB][A][A][B] = 3.8 x 0.24 = 0.91 answer

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