CoF_6^3- absorbs light in the red region of the spectrum, while ColNH, )^\' abso

Question

CoF_6^3- absorbs light in the red region of the spectrum, while ColNH, )^' absorbs tight on the Woe region of. The spectrum. This difference means that a. The splitting of the d orbitals of the two complexes is nearly Identical. b. The d_t^2 and d_x^2 - y^2 orbitals are higher in energy than the d_xy, d_xz, and d_yz orbitals in CoF_6^3-, and just the opposite splitting order for Co(NH_3)_6^3+ c. The crystal field splitting is larger for the ammonia complex than for the fluoride complex. A transition metal complex ion with octahedral geometry has a value of 4.4 times 10^-22 kJ for the crystal field splitting, Delta_o. What is the wavelength for the absorption maximum, lambda for this complex ion? (1 kJ = 1000 J) a. 5.0 times 10^-15 nm b. 452 nm c. 4.5 times 10^-16 nm d. 637 nm

Explanation / Answer

the answer for 15q is c

ammonia being a stronger ligand so splitting is larger compared to fluoride ion which is weak field ligand resulted in absorbances differs to both complexes

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